XmlFindSubNode: Difference between revisions
Jump to navigation
Jump to search
Line 24: | Line 24: | ||
You could use the following code: | You could use the following code: | ||
<syntaxhighlight lang="lua"> | <syntaxhighlight lang="lua"> | ||
maproot = | maproot = getLoadedMapXMLRoot (); | ||
optionsnode = | optionsnode = xmlFindSubNode ( maproot, "options", 0 ); | ||
instructionsnode = | instructionsnode = xmlFindSubNode ( optionsnode, "instructions", 0 ); | ||
</syntaxhighlight> | </syntaxhighlight> |
Revision as of 19:06, 18 May 2006
Description
This function returns a named sub node of a particular XML node.
Syntax
xmlnode xmlFindSubNode ( xmlnode parent, string subnode, int index )
Required Arguments
- parent: This is an xmlnode that you want to find the subnode under. This could be a node returned from another call to xmlFindSubNode.
- subnode: This is the name of the subnode you wish to find.
- index: This is the index of the node you wish to find. For example, to find the 5th subnode with a particular name, you would use 4 as the index value. To find the first occurence, use 0.
Example
If you wanted to find the 'instructions' node in a map file like this:
<map version="2.0"> <options> <instructions>Start at the begining and keep going until the end!</instructions> <options> </map>
You could use the following code:
maproot = getLoadedMapXMLRoot (); optionsnode = xmlFindSubNode ( maproot, "options", 0 ); instructionsnode = xmlFindSubNode ( optionsnode, "instructions", 0 );