XmlCopyFile: Difference between revisions
Jump to navigation
Jump to search
m (→Syntax) |
No edit summary |
||
Line 15: | Line 15: | ||
===Returns=== | ===Returns=== | ||
Returns | Returns the [[xmlnode]] of the copy if the node was successfully copied, ''false'' if invalid arguments were passed. | ||
==Example== | ==Example== |
Revision as of 08:22, 26 August 2013
This function copies all contents of a certain node in a XML document to a new document file, so the copied node becomes the new file's root node.
Syntax
xmlnode xmlCopyFile ( xmlnode nodeToCopy, string newFilePath )
Required Arguments
- nodeToCopy: the xmlnode that is to be copied to a new document.
- newFilePath: the path of the file that is to be created, in the following format: ":resourceName/path". 'resourceName' is the name of the resource the file is in, and 'path' is the path from the root directory of the resource to the file.
- For example, to create a file named 'newfile.xml' with myNode as the root node in the resource 'ctf', it can be done from another resource this way: xmlCopyFile(myNode, ":ctf/newfile.xml").
- If the file is to be in the current resource, only the file path is necessary, e.g. xmlCopyFile(myNode, "newfile.xml").
Returns
Returns the xmlnode of the copy if the node was successfully copied, false if invalid arguments were passed.
Example
In this example we will load an xml file (in the example config.xml) and create a copy in a new folder with the name of copy-config.xml:
local config = xmlLoadFile("config.xml") xmlCopyFile(config, "copy/copy-config.xml")
See Also
- xmlCopyFile
- xmlCreateChild
- xmlCreateFile
- xmlDestroyNode
- xmlFindChild
- xmlLoadFile
- xmlLoadString
- xmlNodeGetAttribute
- xmlNodeGetAttributes
- xmlNodeGetChildren
- xmlNodeGetName
- xmlNodeGetParent
- xmlNodeGetValue
- xmlNodeSetAttribute
- xmlNodeSetName
- xmlNodeSetValue
- xmlSaveFile
- xmlUnloadFile