XmlFindChild: Difference between revisions
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You could use the following code: | You could use the following code: | ||
<syntaxhighlight lang="lua"> | <syntaxhighlight lang="lua"> | ||
local rootNode = xmlLoadFile ( "test.xml" ) | |||
local optionsNode = xmlFindChild ( rootNode, "options", 0 ) | |||
local instructionsNode = xmlFindChild ( optionsNode, "instructions", 0 ) | |||
</syntaxhighlight> | </syntaxhighlight> | ||
</section> | </section> |
Revision as of 16:25, 26 June 2014
This function returns a named child node of an XML node.
Syntax
xmlnode xmlFindChild ( xmlnode parent, string tagName, int index )
Required Arguments
- parent: This is an xmlnode that you want to find the child node under.
- tagName: This is the name of the child node you wish to find (case-sensitive).
- index: This is the 0-based index of the node you wish to find. For example, to find the 5th subnode with a particular name, you would use 4 as the index value. To find the first occurence, use 0.
Returns
Returns an xmlnode if the node was found, false otherwise.
Example
Click to collapse [-]
ServerIf you wanted to find an 'instructions' node in an xml file like this:
<root version="2.0"> <options> <instructions>Start at the beginning and keep going until the end!</instructions> </options> </root>
You could use the following code:
local rootNode = xmlLoadFile ( "test.xml" ) local optionsNode = xmlFindChild ( rootNode, "options", 0 ) local instructionsNode = xmlFindChild ( optionsNode, "instructions", 0 )
See Also
- xmlCopyFile
- xmlCreateChild
- xmlCreateFile
- xmlDestroyNode
- xmlFindChild
- xmlLoadFile
- xmlLoadString
- xmlNodeGetAttribute
- xmlNodeGetAttributes
- xmlNodeGetChildren
- xmlNodeGetName
- xmlNodeGetParent
- xmlNodeGetValue
- xmlNodeSetAttribute
- xmlNodeSetName
- xmlNodeSetValue
- xmlSaveFile
- xmlUnloadFile