XmlLoadFile: Difference between revisions

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xmlnode xmlLoadFile ( string filePath )
xmlnode xmlLoadFile ( string filePath )
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{{OOP||XML.load||}}
===Required Arguments===  
===Required Arguments===  
*'''filePath:''' The [[filepath]] of the file in the following format: '''":resourceName/path"'''. 'resourceName' is the name of the resource the file is in, and 'path' is the path from the root directory of the resource to the file.
*'''filePath:''' The [[filepath]] of the file in the following format: '''":resourceName/path"'''. 'resourceName' is the name of the resource the file is in, and 'path' is the path from the root directory of the resource to the file.

Revision as of 20:38, 12 July 2014

This function provides an alternative way to load XML files to getResourceConfig. This function loads an XML file and returns the node by specifying a specific file path, while getResourceConfig allows for loading an XML file from a resource.

Syntax

xmlnode xmlLoadFile ( string filePath )

OOP Syntax Help! I don't understand this!

Method: XML.load(...)


Required Arguments

  • filePath: The filepath of the file in the following format: ":resourceName/path". 'resourceName' is the name of the resource the file is in, and 'path' is the path from the root directory of the resource to the file.
For example, if there is a file named 'settings.xml' in the resource 'ctf', it can be accessed from another resource this way: xmlLoadFile(":ctf/settings.xml").
If the file is in the current resource, only the file path is necessary, e.g. xmlLoadFile("settings.xml").

Returns

Returns the root xmlnode object of an xml file if successful, or false otherwise.

Example

This example loads an XML file called settings.xml that is in a resource called ctv.

node = xmlLoadFile ( ":ctv/settings.xml" )

See Also