XmlNodeGetChildren
Jump to navigation
Jump to search
This function returns a single sub node or a list of sub nodes of a particular XML node.
Syntax
xmlnode/table xmlNodeGetSubNodes( xmlnode parent[, int index])
Required Arguments
- parent: This is an xmlnode that you want to find the sub nodes under.
Optional Arguments
NOTE: When using optional arguments, you might need to supply all arguments before the one you wish to use. For more information on optional arguments, see optional arguments.
- index: This is the index of the node you wish to find. For example, to find the 5th subnode, you would use 4 as the index value. To find the first occurence, use 0. If this is not set, it will return a list of all sub nodes.
Returns
If index isn't specified, it returns a list of all sub nodes. Returns an xmlnode object if index was set and a node was found, otherwise it returns false.
Example
Click to collapse [-]
ServerIf you wanted to find the 'instructions' node in a map file like this:
<map version="2.0"> <options> <instructions>Start at the begining and keep going until the end!</instructions> </options> </map>
You could use the following code:
maproot = getLoadedMapXMLRoot (); optionsnode = xmlNodeGetSubNodes( maproot, 0 ); -- In this case it would find the options sub node as the first under the 'map' node
See Also
- xmlCopyFile
- xmlCreateChild
- xmlCreateFile
- xmlDestroyNode
- xmlFindChild
- xmlLoadFile
- xmlLoadString
- xmlNodeGetAttribute
- xmlNodeGetAttributes
- xmlNodeGetChildren
- xmlNodeGetName
- xmlNodeGetParent
- xmlNodeGetValue
- xmlNodeSetAttribute
- xmlNodeSetName
- xmlNodeSetValue
- xmlSaveFile
- xmlUnloadFile