PregReplace: Difference between revisions

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This function performs a regular expression search and replace and returns the replaced string.
This function performs a regular expression search and replace and returns the replaced string.
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{{Warning|When declaring a pattern string in quotes, the backslash character should be doubled up. e.g. "\\(" will match a single bracket.}}  
{{Warning|When declaring a pattern string in quotes, the backslash character should be doubled up. e.g. "\\(" will match a single bracket. This also applies to the replacement string.}}  
{{Warning|Multiline flag does not work correctly}}
{{Warning|Multiline flag does not work correctly}}


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Some examples:
Some examples:
<syntaxhighlight lang="lua">
<syntaxhighlight lang="lua">
addCommandHandler( 'examples',
addCommandHandler('examples',
function( )
    function ()
                -- Replace doh with done
        -- Replace doh with done
outputDebugString( pregReplace( 'I doh this, guys.', 'doh', 'done' ) or 'not replaced' ) -- Result: I done this, guys
        outputDebugString( pregReplace( 'I doh this, guys.', 'doh', 'done' ) or 'not replaced' ) -- Result: I done this, guys
                -- Remove all uppercase alphabetic characters
 
                outputDebugString( pregReplace( 'AaaBbbZzz', '[A-Z]{1,}', '' ) or 'not replaced' ) -- Result: aabbzz
        -- Remove all uppercase alphabetic characters
end
        outputDebugString( pregReplace( 'AaaBbbZzz', '[A-Z]{1,}', '' ) or 'not replaced' ) -- Result: aabbzz
 
        -- Use simple backreference in replacement string
        outputDebugString( pregReplace( "I love Lua!", "(Lua)", "Moon\\1" ) ) -- Result: I love MoonLua!
 
        -- Remove repeated characters
        outputDebugString( pregReplace( "Keeeeeep this shooooooort.", "((.)\\2{2})\\2+", "\\1" ) ) -- Result: Keeep this shooort.
    end
)
)
</syntaxhighlight>
</syntaxhighlight>

Revision as of 21:19, 12 July 2016

This function performs a regular expression search and replace and returns the replaced string.

[[|link=|]] Warning: When declaring a pattern string in quotes, the backslash character should be doubled up. e.g. "\\(" will match a single bracket. This also applies to the replacement string.
[[|link=|]] Warning: Multiline flag does not work correctly

Syntax

string pregReplace ( string subject, string pattern, string replacement [, int/string flags ] )

Required Arguments

  • subject: The input string.
  • pattern: The pattern string to search for in the input string.
  • replacement: The replacement string to replace all matches within the input string.

Optional Arguments

  • flags: Conjuncted value that contains flags ( 1 - ignorecase, 2 - multiline, 4 - dotall, 8 - extended ) or ( i - Ignore case, m - Multiline, d - Dotall, e - Extended )

Returns

Returns the replaced string, or bool false otherwise.

Example

Click to collapse [-]
Shared ( client and server )

Some examples:

addCommandHandler('examples',
    function ()
        -- Replace doh with done
        outputDebugString( pregReplace( 'I doh this, guys.', 'doh', 'done' ) or 'not replaced' ) -- Result: I done this, guys

        -- Remove all uppercase alphabetic characters
        outputDebugString( pregReplace( 'AaaBbbZzz', '[A-Z]{1,}', '' ) or 'not replaced' ) -- Result: aabbzz

        -- Use simple backreference in replacement string
        outputDebugString( pregReplace( "I love Lua!", "(Lua)", "Moon\\1" ) ) -- Result: I love MoonLua!

        -- Remove repeated characters
        outputDebugString( pregReplace( "Keeeeeep this shooooooort.", "((.)\\2{2})\\2+", "\\1" ) ) -- Result: Keeep this shooort.
    end
)

Requirements

This template will be deleted.

See Also